3x^2-13x-940=0

Solution for 3x^2-13x-940=0 equation:

3x^2-13x-940=0

a = 3; b = -13; c = -940;
Δ = b2-4ac
Δ = -132-4·3·(-940)
Δ = 11449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11449}=107$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-107}{2*3}=\frac{-94}{6}
=-15+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+107}{2*3}=\frac{120}{6}
=20
$